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javascript includes() case insensitive

I have an array of strings that I need to loop and check against with another passed in string.

var filterstrings = ['firststring','secondstring','thridstring'];
var passedinstring = localStorage.getItem("passedinstring");

for (i = 0; i < filterstrings.lines.length; i++) {
    if (passedinstring.includes(filterstrings[i])) {
        alert("string detected");
    }
}

How do I ensure that case sensitivity is ignored here (preferably by using regex) when filtering, if the var passedinstring were to have strings like FirsTsTriNg or fiRSTStrING?

over 4 years ago · Santiago Trujillo
3 answers
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0

You can create a RegExp from filterstrings first

var filterstrings = ['firststring','secondstring','thridstring'];
var regex = new RegExp( filterstrings.join( "|" ), "i");

then test if the passedinstring is there

var isAvailable = regex.test( passedinstring ); 
over 4 years ago · Santiago Trujillo Report

0

You can simply convert the passedinstring to lowercase.

var passedinstring = localStorage.getItem("passedinstring").toLowerCase();
over 4 years ago · Santiago Trujillo Report

0

ES6 array method filter() can simplify the solution to a single line. Use includes() method to determine whether an array includes a certain value among its entries in conjunction to the toLowerCase() method to convert it to lowercase.

var filterstrings = ['firststring','secondstring','thridstring'];
var passedinstring = localStorage.getItem("passedinstring");

// convert each string from filterstrings and passedinstring to lowercase
// to avoid case sensitive issue.
filteredStrings = filterstrings.filter((str) => str.toLowerCase().includes(passedinstring.toLowerCase())
over 4 years ago · Santiago Trujillo Report
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