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Javascript Error: IPython is not defined in JupyterLab

I have the latest/updated Anaconda package. Everytime I try to plot something using python 3.6.6 I get the following error in JupyterLab...

Javascript Error: IPython is not defined

When I run the same code in Spyder using an ipython kernel, it works just fine. Have been looking all over online but cant seem to figure out what is going on. Any help would be appreciated.

over 4 years ago · Santiago Trujillo
3 answers
Answer question

0

Jupyter Lab does support interactive matplotlib through the jupyter-matplotlib extension. The installation procedure is slightly more involved, but works fine. Since the ipympl Jupyter Lab version requires NodeJS, and NodeJS requires Windows 8.1, ipympl also has this requirement.

As before, it is important to invoke the iPython magic command before plotting:

Usage:

%matplotlib widget

Installation:

Note: If using this extension with Jupyter Lab, it's recommended to use a version >= 3. For more detailed instructions on installing an old extension than below, see the instructions on ipympl github.

Using conda

conda install -c conda-forge ipympl

# If using JupyterLab 2
conda install nodejs
jupyter labextension install @jupyter-widgets/jupyterlab-manager
jupyter lab build

# Later, if updating a previous Lab install:
conda install ipympl
jupyter lab build

Using pip

pip install ipympl

# If using JupyterLab 2
pip install nodejs
jupyter labextension install @jupyter-widgets/jupyterlab-manager
jupyter labextension install jupyter-matplotlib
over 4 years ago · Santiago Trujillo Report

0

Jupyter Lab does support interactive matplotlib through the jupyter-matplotlib extension. See TomNorway's answer.

Alternatively, you can configure matplotlib to use inline instead. inline is not as powerful as interactive, but it can save you.

To use inline, add this line before plot the graph:

    %matplotlib inline

More Info

over 4 years ago · Santiago Trujillo Report

0

Encountered similar issue when using backtrader. This fixed it for me:

cerebro.plot(iplot = False)
over 4 years ago · Santiago Trujillo Report
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