Goal: Use an array method to remove the strings get, right, the, first, time and replace them with the single string know in secretMessage array.
Plan Define a function to text in the rain, the old string, and the new string and use to .replaceall() methods and pass each one of the different arguments through one at a time, reassigning the array each call.
Code Thus Far
let secretMessage = ['Learning', 'is', 'not', 'about', 'what', 'you', 'get', 'easily', 'the', 'first', 'time,', 'it', 'is', 'about', 'what', 'you', 'can', 'figure', 'out.', '-2015,', 'Chris', 'Pine,', 'Learn', 'JavaScript'];
function replaceWords(orginalArray,oldString,updatedString){=
let updatedArray= orginalArray.replaceAll(oldString,updatedString);//Not Sure If I need to wrap this in []
return updatedArray;
}
secretMessage = replaceWords(secretMessage,'get','know');
secretMessage = replaceWords(secretMessage,'right','know');
secretMessage = replaceWords(secretMessage,'the','know');
secretMessage = replaceWords(secretMessage,'first','know');
secretMessage = replaceWords(secretMessage,'time','know');
console.log(secretMessage);Current Results
let updatedArray= orginalArray.replaceAll(oldString,updatedString);
^
TypeError:
orginalArray.replaceAll is not a function at replaceWords
As stated by @Pointy's comment, replaceAll() is a string method, it's not available on an array.
So we'll need a way to apply something on each array index.
Luckily map() does exactly that:
The
map()method creates a new array populated with the results of calling a provided function on every element in the calling array.
let secretMessage = ['Learning', 'is', 'not', 'about', 'what', 'you', 'get', 'easily', 'the', 'first', 'time,', 'it', 'is', 'about', 'what', 'you', 'can', 'figure', 'out.', '-2015,', 'Chris', 'Pine,', 'Learn', 'JavaScript'];
function replaceWords(orginalArray,oldString,updatedString){
return orginalArray.map(item => {
return item.replaceAll(oldString, updatedString)
});
}
secretMessage = replaceWords(secretMessage,'get','know');
secretMessage = replaceWords(secretMessage,'right','know');
secretMessage = replaceWords(secretMessage,'the','know');
secretMessage = replaceWords(secretMessage,'first','know');
secretMessage = replaceWords(secretMessage,'time','know');
console.log(secretMessage);replaceAll is String function, not an Array function. If you want to replace a word that maybe exists as value in an array, you have to walk through that array. Your code would look like this:
let secretMessage = ['Learning', 'is', 'not', 'about', 'what', 'you', 'get', 'easily', 'the', 'first', 'time,', 'it', 'is', 'about', 'what', 'you', 'can', 'figure', 'out.', '-2015,', 'Chris', 'Pine,', 'Learn', 'JavaScript'];
function replaceWords(orginalArray,oldString,updatedString){
/* because your array values are just single words
and you want to replace the whole word with another whole word,
you can use string comparison instead of replaceAll() */
let updatedArray= orginalArray.map(string => (string == oldString ? updatedString : string));
return updatedArray;
}
secretMessage = replaceWords(secretMessage,'get','know');
secretMessage = replaceWords(secretMessage,'right','know');
secretMessage = replaceWords(secretMessage,'the','know');
secretMessage = replaceWords(secretMessage,'first','know');
secretMessage = replaceWords(secretMessage,'time','know');
console.log(secretMessage);Just for "fun", a solution using both an array method (Array.prototype.join()) and replaceAll() (String.prototype.replaceAll()) and close to your original idea, could be:
function replaceWords(arr, oldStr, newStr) {
return arr.join(' ') // join all the array items into a single space-separated string
.replaceAll(oldStr, newStr) // call `replaceAll()` on the newly created string
.split(' '); // split the string back into an array
}
let secretMessage = ['Learning', 'is', 'not', 'about', 'what', 'you', 'get', 'easily', 'the', 'first', 'time,', 'it', 'is', 'about', 'what', 'you', 'can', 'figure', 'out.', '-2015,', 'Chris', 'Pine,', 'Learn', 'JavaScript'];
secretMessage = replaceWords(secretMessage, 'get', 'know');
secretMessage = replaceWords(secretMessage, 'right', 'know');
secretMessage = replaceWords(secretMessage, 'the', 'know');
secretMessage = replaceWords(secretMessage, 'first', 'know');
secretMessage = replaceWords(secretMessage, 'time', 'know');
console.log(secretMessage);Having said that, I think nobody would do it in that way in real life ;)