quick basic question,
When setting up guildmember.timout with discord.js v13, it gives an example with .then(console.log) and .catch(console.error). Using the example, the code will continue after the .catch.
muteMember
.timeout(time, reason)
.catch((error) => {
return errors(client, message, args, "mute", error, true);
});
muteMember.send ...
At the moment it will run the errors function then continue onto the code after the .catch, for example muteMember.send. What's the best way to have it "stop" after it runs what is inside of the .catch? Thank you in advance
You can make it return a falsy if the error occurs, then check if it is falsy, and return if it is.
let isModified = await muteMember
.timeout(time, reason)
.catch((error) => {
errors(client, message, args, "mute", error, true)
return false;
})
if (!isModified) return;
You can use async-await with try-catch:
async function myFunction()
{
try
{
await muteMember.timeout(time, reason)
// throws an error if it fails -- jumps to the catch block
muteMember.send...
}
catch(error)
{
errorcheck = true
errors(client, message, args, "mute", error, true);
// and whatever other error handling you would like
}
}The return statement only returns out of the #catch callback. Handle the promise with a #then callback, thats where you want your code to run when its successful.
muteMember
.timeout(time, reason)
.catch((error) => {
//error
errorcheck = true
return errors(client, message, args, "mute", error, true);
})
.then(() => {
//success
})