I'm building a component that allows me to compare two objects. It accepts a list of fields to compare and a list of fields that need to be ignored in string format
Here is an example of the object that will be compared:
{
// (..... More elements above .....)
taskData: {
"uniqueId": "OrdenTrabajo48",
"id": 48,
"position": 1,
"name": "Dirección Obra Civil",
"description": "Dirección Obra Civil Afecta: Sorda, Roberto",
"startDate": "2021-10-16T11:00:00.000Z",
"endDate": "2022-06-01T11:00:00.000Z",
"duration": 227,
"progress": 73,
"hours": 0,
"realHours": 15,
"predecessor": null,
"child": [],
"resourceInfo": [
{
"uniqueId": "Persona_1MJ0VE9G0",
"id": "OrdenTrabajo48Persona_1MJ0VE9G0",
"name": "Sorda, Roberto",
"group": "Subgerencia de Planes y Proyectos - SUB_PLAN_PROY_SIT",
"unit": 4.1667,
"startDate": "2021-10-16T03:00:00.000+00:00",
"endDate": "2022-06-01T02:59:59.000+00:00",
"hours": 0,
"realHours": 15,
"avatar": "http://localhost:8091/images/llama.jpg"
}
],
"comments": null,
"etiquetas": [],
"baseLineStartDate": null,
"baseLineEndDate": null
}
// (..... More elements below .....)
}
(But to clarify, it could be any object. The component is abstract and can be used anywhere)
The component doesn't know the structure of the object to compare, just the object and the paths in string format
I want to remove in every element of the array resourceInfo, the properties avatar, icon, label and color regardless the length of the array, but I don't know if there is a syntax to do that.
Also I want to remove the property realHours
This is what I tried:
const ignoredFields = [
'taskData.resourceInfo[?].avatar', //<--- It's not working
'taskData.resourceInfo[].icon', //<--- Neither this
'taskData.resourceInfo.label', //<--- Or this
'taskData.resourceInfo[0].color', //<--- This hardcode is working, but I don't know the length in that scope
'taskData.realHours' // <-- No problems here
];
const currentComparableObject = _.omit(obj, ignoredFields);
const oldComparableObject = _.omit(prev, ignoredFields);
var fieldsToOmit=[];
var resourceInfoFields=['avatar','icon','label','color'];
var globalFields=['realHours'];
taskData.resourceInfo.forEach((item,index)=>{
resourceInfoFields.forEach((field)=>{
fieldsToOmit.push(`resourceInfo[${index}].${field}`)
})
})
console.log( _.omit(taskData, fieldsToOmit.concat(globalFields)))
You can remove properties in a functional manner (immutable) by using destructuring:
const {realHours, ...result} = {
...taskData,
resourceInfo: taskData.resourceInfo.map(
({avatar, icon, label, color, ...keep}) => keep
)
};
console.log(result);
Thanks for the answers to all.
To solve partially the problem, I created a function that does the following:
It filters the references that contains [?] (i.e: taskData.resourceInfo[?].avatar)
Then obtain the first part of the string (That is, the path to reach the array) and the second part (property name)
Using _.get from lodash it retrieves the length of the array and creates a new fieldReference with the index, so loadash can read it.
private sanitizeArrays(obj: any, fieldReferences: string[]): string[] {
const fieldsDup = [...fieldReferences];
// Get Elements that contains [?] in the property name
const arrays = fieldsDup.filter(ignoredField => ignoredField.match(/\[\?]/g));
// Remove elements that contain [?] from ignoredFieldsDuplicated
fieldsDup.forEach((ignoredField, index) => {
if (ignoredField.includes('[?]')) {
fieldsDup.splice(index, 1);
}
});
// Get the properties names without [?]
const arrayPropertyName = arrays.map(ignoredField => ignoredField.split('[')[0]);
const afterArrayPropertyName = arrays.map(ignoredField => ignoredField.split(']')[1]);
// For each array that I have...
arrayPropertyName.forEach((array, index) => {
const length = _.get(obj, array).length;
for (let i = 0; i < length; i++) {
fieldsDup.push(array + '[' + i + ']' + afterArrayPropertyName[index]);
}
});
return fieldsDup;
}
Example input (if the object contains only one element in resourceInfo):
'taskData.resourceInfo[?].avatar',
'taskData.resourceInfo[?].icon',
'taskData.resourceInfo[?].label',
'taskData.resourceInfo[?].color',
'taskData.resourceInfo[?].fontColor',
'taskData.realHours'
Example output:
taskData.resourceInfo[?].icon
taskData.resourceInfo[?].color
taskData.realHours
taskData.resourceInfo[0].avatar
taskData.resourceInfo[0].icon
taskData.resourceInfo[0].label
taskData.resourceInfo[0].color
taskData.resourceInfo[0].fontColor
(javascript includes() isn't playing nice deleting the [?])
Also it doesn't work for nested arrays...