so i wanted my for loop to run trough a text, and count how many times the words: 'really', 'basically' and 'very' were mentioned.
here is the text:
let story = 'Last weekend, I took a very beautiful bike ride of my life. The route is called "The 9W to Nyack" and it actually stretches all the way from Riverside Park in Manhattan to South Nyack, New Jersey. It's really an adventure from beginning to end! It is a 48 mile loop and it basically took me an entire day. I stopped at Riverbank State Park to take some very artsy photos. It was a really short stop, though, because I had a really long way left to go.' ;
let storyWords= story.split(' ');
this is the function:
function count() {
let reallycount = 0;
let verycount =0;
let basicallycount = 0;
for (let i = 0; i < storyWords.length; i++) {
if (storyWords[i] === 'really'){
reallycount += 1;
console.log ('really count :' + reallycount);
} else if ( storyWords[i] === 'very'){
verycount += 1;
console.log ('very count :' + verycount);
} else if ( storyWords[i] === 'basically'){
basicallycount += 1;
console.log ('basically count :' + basicallycount);
}
}
} count();
The results:
very count :1, really count :1, basically count :1, very count :2, really count :2, really count :3,
My question: so i only want the last result of very-, bascially-, and reallycount to show. in other words i want the results to be:
basically count :1, very count :2, really count :3,
how can i hide/remove the other results?
Here is a slightly more universal form of your counts() function that works more in a functional way:
const story = `Last weekend, I took a very beautiful bike ride of my life. The route is called "The 9W to Nyack" and it actually stretches all the way from Riverside Park in Manhattan to South Nyack, New Jersey. It's really an adventure from beginning to end! It is a 48 mile loop and it basically took me an entire day. I stopped at Riverbank State Park to take some very artsy photos. It was a really short stop, though, because I had a really long way left to go.` ;
function counts(str, words){
const arr=str.toLowerCase().split(/\s+/);
return arr.reduce((a,w)=>{
if(words.indexOf(w)>-1) a[w]=(a[w]||0)+1
return a
}, {} )
}
console.log(counts(story,["really","actually","very"]));You can extract it to variables and console log it afterwards
function count() {
let reallycount = 0;
let verycount = 0;
let basicallycount = 0;
for (let i = 0; i < storyWords.length; i++) {
if (storyWords[i] === "really") {
reallycount += 1;
} else if (storyWords[i] === "very") {
verycount += 1;
} else if (storyWords[i] === "basically") {
basicallycount += 1;
}
}
console.log("basically count :" + basicallycount);
console.log("very count :" + verycount);
console.log("really count :" + reallycount);
}
count();
Another option for counting the number of times a word occurs is by using the filter function
const story = "Last weekend, I took a very beautiful bike ride of my life. The route is called "The 9W to Nyack" and it actually stretches all the way from Riverside Park in Manhattan to South Nyack, New Jersey. It's really an adventure from beginning to end! It is a 48 mile loop and it basically took me an entire day. I stopped at Riverbank State Park to take some very artsy photos. It was a really short stop, though, because I had a really long way left to go."
const storyWords = story.split(" ")
function count() {
const basicallycount = storyWords.filter(word => word === "basically").length
const verycount = storyWords.filter(word => word === "very").length
const reallycount = storyWords.filter(word => word === "really").length
console.log(`basically count: ${basicallycount}`
console.log(`very count: ${verycount}`
console.log(`really count: ${reallycount}`
}
count();