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No hay depurador disponible, no se puede enviar el problema de 'variables'

Estoy tratando de practicar For loop y soy nuevo en la codificación en general. Cuando trato de ejecutar mi programa, me da un error que dice "No hay depurador disponible, no se pueden enviar 'variables'. ¿Qué debo hacer para solucionarlo?

 function trekkingMania(input) { let index = 0; let groups = Number(input[index]); index++; let musala = 0; let monBlan = 0; let kilimanjaro = 0; let k2 = 0; let everest = 0; let totalPeople = 0; for (let i = 0; i < groups; i++) { let climbers = Number(input[index]); index++; totalPeople = totalPeople + climbers; if (climbers <= 5) { musala = musala + climbers; } else if (climbers >= 6 && climbers <= 12) { monBlan = monBlan + climbers; } else if (climbers >= 13 && climbers <= 25) { kilimanjaro = kilimanjaro + climbers; } else if (climbers >= 26 && climbers <= 40) { k2 = k2 + climbers; } else { everest = everest + climbers; } } let musalaPercent = musala / totalPeople * 100; let monBlanPercent = monBlan / totalPeople * 100; let kilimanjaroPercent = kilimanjaro / totalPeople * 100; let k2Percent = k2 / totalPeople * 100; let everestPercent = everest / totalPeople * 100; console.log(`${musalaPercent.toFixed(2)}%`); console.log(`${monBlanPercent.toFixed(2)}%`); console.log(`${kilimanjaroPercent.toFixed(2)}%`); console.log(`${k2Percent.toFixed(2)}%`); console.log(`${everestPercent.toFixed(2)}%`);

}

about 4 years ago · Santiago Trujillo
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