Here is my first array:
const withSub = [[31, 32, 34, 34], [32, 36], [12], [15, 38]];
Here is my second array:
const arr = ['f', 'b', 'c', 'd'];
The number of arrays in withSub is always equal to the number of arr arrays, while the number of subarrays in withSub may be different.
I want to create a function that generates a new array based on these two arrays in such a way that the number of each element in arr must be equal to the number of subarrays in withArr.
In this example the final array must be:
['f', 'f', 'f', 'f', 'b', 'b', 'c', 'd', 'd'];
If I understood your question correctly, you can use .flatMap() on your withSub array to map each number within each subarray to their corresponding letter from arr. You can do this by taking the index of the subarray from the flatMap callback, and then use that to obtain the letter from arr when mapping your subarrays.
See example below:
const withSub = [[31, 32, 34, 34], [32, 36], [12], [15, 38]];
const arr = ['f', 'b', 'c', 'd'];
const res = withSub.flatMap((subArr, i) => subArr.map(() => arr[i]));
console.log(res);you can do something as the following code:
const generate = (numbers, letters) => {
return numbers.map((nums, i) => {
return nums.map(num => letters[i])
}).flat()
}
And then use it with generate(withSub, arr).
You can have an approach with forEach() and spread operator.
forEach() is similar to a forloop with subtle differences.
const awesomeFunction = (withSub , arr) => {
let ans = [];
arr.forEach( (x,index) => {
let newArr = new Array(withSub[index].length).fill(x);
ans = [...ans , ...newArr];
});
return ans; };
const withSub = [[31, 32, 34, 34], [32, 36], [12], [15, 38]];
const arr = ['f', 'b', 'c', 'd'];
console.log(awesomeFunction(withSub,arr));