I have an array like this:
var clients=[{"id":1,"name":"john","age":20},
{"id":3,"name":"dean","age":23},
{"id":12,"name":"harry","age":14},
{"id":1,"name":"sam","age":22},
{"id":13,"name":"Bolivia","age":16},
{"id":7,"name":"sabi","age":60},
{"id":7,"name":"sahra","age":40},
{"id":4,"name":"natie","age":53},{"id":7,"name":"many","age":22}]
I want to find the duplicate objects and cluster them like this:
[
{
"id":1,
"clients":[
{"id":1,"name":"john","age":20},
{"id":1,"name":"sam","age":22}
]
},
{
"id":7,
"clients":[
{"id":7,"name":"sabi","age":60},
{"id":7,"name":"sahra","age":40},
{"id":7,"name":"many","age":22}
]
}
]
can I do that with filter() like this:clients.reduce(//code hier)?
reduce() is tailor made for this. When you want to aggregate over an array and get a computed result, you should use reduce().
find() is another array method, which helps in finding an array element based on a condition (here the matching of id property).
var clients=[{"id":1,"name":"john","age":20},
{"id":3,"name":"dean","age":23},
{"id":12,"name":"harry","age":14},
{"id":1,"name":"sam","age":22},
{"id":13,"name":"Bolivia","age":16},
{"id":7,"name":"sabi","age":60},
{"id":7,"name":"sahra","age":40},
{"id":4,"name":"natie","age":53},{"id":7,"name":"many","age":22}]
let ans = clients.reduce((agg,x,index) => {
let findI = agg.find( a =>
a.id === x.id
);
if(findI) findI.clients.push(x);
else {
agg.push({
id : x.id,
clients : [x]
});
}
return agg;
},[]);
console.log(ans);The simplest solution would be to loop over the clients and check for an existing object with the same id. If yes, push to clients array. Or else, just create one.
var clients = [{ "id": 1, "name": "john", "age": 20 },
{ "id": 3, "name": "dean", "age": 23 },
{ "id": 12, "name": "harry", "age": 14 },
{ "id": 1, "name": "sam", "age": 22 },
{ "id": 13, "name": "olivia", "age": 16 },
{ "id": 7, "name": "sabi", "age": 60 },
{ "id": 7, "name": "sahra", "age": 40 },
{ "id": 4, "name": "natie", "age": 53 }, { "id": 7, "name": "kany", "age": 22 }]
const groups = [];
for (let client of clients) {
const existingGroup = groups.find(group => group.id == client.id)
if (existingGroup)
existingGroup.clients.push(client);
else {
groups.push({ id: client.id, clients: [client] });
}
}
console.log(groups);You can reassign the original object with the temporary object just used for this, and continue with your business logic, which I believe is the one you are looking for.