Here is my code and the problem is whether you search for "remember" or "member" it returns the result.As 'remember' has 'member' and I just want to search for exact matches. I should not return anything when I search for 'member'.
txt= `38
00:04:17.795 --> 00:04:23.551
Two previous cases
were open and shut.
39
00:04:23.601 --> 00:04:29.140
It was January 3, 1995,
my daughter's birthday.
40
00:04:29.140 --> 00:04:30.441
I remember.`
const searchedWord = 'member';
var res = txt
.toLowerCase()
.split('\n\n')
.filter((x) => {
return x.includes(searchedWord.toLowerCase());
});
console.log(res);It sounds like you want to require word breaks on either side of the word you're searching for. You can do that with a regular expression:
const searchRegex = /\bmember\b/i; // ***
var res = txt
.toLowerCase()
.split('\n\n')
.filter((x) => {
return searchRegex.test(x); // ***
});
Live Example:
const txt = `38
00:04:17.795 --> 00:04:23.551
Two previous cases
were open and shut.
39
00:04:23.601 --> 00:04:29.140
It was January 3, 1995,
my daughter's birthday.
40
00:04:29.140 --> 00:04:30.441
I remember.
41
He was a member of the club
42
Something else`;
const searchRegex = /\bmember\b/i;
var res = txt
.toLowerCase()
.split('\n\n')
.filter((x) => {
return searchRegex.test(x);
});
console.log(res);If you need to create the regular expression dynamically (that is, starting with a string variable or similar containing "member"), see this question's answers and, if relevant, this one's.