In my project I have an array, holding thousands of objects. I need to search for an explicit object inside the array. When the match is found, I need to be able to access the object properties. Because of performance I want to use Javascript's .some() function. But with the code I have so far I only get a 'true' as return. How can I access the properties inside when the if-statement is a hit?
My code:
let array = [
{object.uid: 'one',
object.value: 'Hello one'},
{object.uid: 'two',
object.value: 'Hello two'},
{object.uid: 'three',
object.value: 'Hello three'}]
if (array.some(e => e.uid == "two")){
//how do I get object.value here?
};
You need to use find() method instead of some()
let array = [
{uid: 'one',
value: 'Hello one'},
{uid: 'two',
value: 'Hello two'},
{uid: 'three',
value: 'Hello three'}]
const obj = array.find(e => e.uid == "two");
if (obj){
console.log(obj)
};