Business
Jobs
  • About Us
  • Solutions
    • Job Postings
      Post your job and receive qualified candidates in 48h.
    • Candidate Assessments
      500+ technical and psychological tests, plus anti-fraud.
    • Headhunting
      Tailor-made executive search from start to finish.
    • Payroll + EOR
      Payroll dispersal and EOR across 15+ LATAM countries.
  • Pricing
  • Jobs

0

160
Views
GraphQL result for another mutation

Is it meanwhile possible to use the result of a GraphQL mutation as a parameter for another mutation?

I would like to create a user and his address together in one call.

First I write the address and then take the address id for the creation of the user. Filling the necessary data via the inputs works perfectly

Is this possible without triggering a new mutation from the client?

const createUser = gql`
  mutation createUser(
    $user: createUserInput!
    $address: createAddressInput!
  ) {
    createAddress(input: $address) {
      address {
        id       
      }
    }
    createUser(input: $user ) {
      user {
        id
        username
      }
    }
  }
`
about 4 years ago · Juan Pablo Isaza
1 answers
Answer question

0

No, this is not possible. You either have to make two sequential requests from the client, or adapt your server implementation. I recommend the latter.

You should change your schema so that the CreateUserInput type to not only accepts an addressId: ID but alternatively can accept a newAddress: CreateAddressInput object, which it will then use to create a new address before creating a new user.

about 4 years ago · Juan Pablo Isaza Report
Answer question
Find remote jobs

Discover the new way to find a job!

Top jobs
Top job categories
Business
Post vacancy Pricing Sales
Legal
Terms and conditions Privacy policy
© 2026 PeakU Inc. All Rights Reserved.
Andres GPT
Show me some job opportunities
There's an error!