I have a sorted dictionary with certain number of entries:
dict = {B:3, A:2, C:2, D:1, E:0, F:0...}
After filtering the dictionary to get only the entries with top 3 largest values:
result = Object.fromEntries(Object
.entries(dict)
.sort(([, a], [, b]) => b - a)
.filter((s => ([, v]) => s.add(v).size <= 3)(new Set))
);
The current dictionary is
{"B": 3, "A": 2, "C": 2, "D": 1}
So I am trying to add 4 to the largest values,2 to the second largest values and 1 to the third largest values, what are the ways to do this?
The expected output: {"B": 7, "A": 4, "C": 4, "D": 2}
One of the ways I can think of is:
for (const key of Object.keys(result)) {
// if result[key] largest
//plus 4
// if result[key] second largest
//plus 2
// else
//plus 1
}
Thanks for reading..
You can do this using Map and flatMap as:
const dict = { B: 3, A: 2, C: 2, D: 1, E: 0, F: 0 };
const valuesToAdd = [4, 2, 1];
const result = Object.fromEntries([
...Object.entries(dict)
.sort(([, a], [, b]) => b - a)
.filter( ( (s) => ([, v]) => s.add(v).size <= 3 )(new Set()) )
.reduce((map, arr) => {
const [k, v] = arr;
map.has(v) ? map.get(v).push(arr) : map.set(v, [arr]);
return map;
}, new Map())
.values(),
].flatMap((arr, i) => arr.map(([k, v]) => [k, v + valuesToAdd[i]]))
);
console.log(result);