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Regex Match phrases with or without quotation

im new to regular expressions and i want to build an expression that finds the below pattern:

We have the string:

"'Hello world',dude, 'Somethings, never, turn and go', bye" 

I want a regular expression that gives this result:

['Hello world',dude,'Somethings, never, turn and go',bye]

Basically, splitting the string on comma but keeping the phrases with quotes that have comma as a whole.

I tried this ('\s*,\s*') but doesnt work.

about 4 years ago · Juan Pablo Isaza
2 answers
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0

Maybe try (?<=')\s*,\s*|\s*,\s*(?=')

let s = "'Hello world',dude, 'Somethings, never, turn and go', bye";
let arr = s.split(new RegExp(String.raw`(?<=')\s*,\s*|\s*,\s*(?=')`, 'g'));
console.log(arr)

about 4 years ago · Juan Pablo Isaza Report

0

I think you want something like:

const regex = /(?:\'.*?\')|(?:\w+)/g;

const str = "'Hello world',dude, 'Somethings, never, turn and go', bye";

console.log(str.match(regex));

about 4 years ago · Juan Pablo Isaza Report
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