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How to use await with forEach in Javascript?

I'm trying to use PokeAPI with JS.

I can get Pokeman information successfully and display it, but not in the right order.

I used a forEach loop and would like to wait until I add the first Pokeman and then add the second...

I've discovered await and I tried to use it but I can't do it. Can someone help me please?

Here is my JS code :

var url = 'https://pokeapi.co/api/v2/pokemon/';

fetch(url)
  .then(function(response) {
    return response.json();
  })
  .then(function(response) {
    response.results.forEach(element => {
      var url = 'https://pokeapi.co/api/v2/pokemon/' + element.name;
      fetch(url)
        .then(function(response) {
          return response.json();
        })
        .then(function(response) {
          addPokemon(response.name, response.sprites.front_default, response.types[0].type.name, response.height, response.weight);
        })
    });
  })

about 4 years ago · Juan Pablo Isaza
3 answers
Answer question

0

You can use 'for' loop instead of forEach.

for (let i = 0; i < length; i++) {
  const poke = await fetch(...);
}
about 4 years ago · Juan Pablo Isaza Report

0

Promise.all(response.results.map(...)).then(
about 4 years ago · Juan Pablo Isaza Report

0

It looks like you're using Promises but not the async/await syntax.

You can use a forEach with async await, since the code can be written in a way that "looks" synchronous.

Right now, you're just executing multiple Promises one after another within the forEach loop. I would probably chain the promises together and then await Promise.all() to do something useful after they have all fulfilled.

about 4 years ago · Juan Pablo Isaza Report
Answer question
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