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Javascript - find highest value in an object of arrays of objects

I have an object containing arrays of objects. I'm trying to find the highest value of an object property, 'sortOrder' without manually iterating through the arrays and objects.

So my variable looks like this following:

const myObj = {
 people: [
   0: {firstname: 'Dave', lastName: 'Jones', sortOrder: 22},
   1: {firstname: 'Jane', lastName: 'Smith', sortOrder: 11}
 ],
 otherPeople: [
   0: {firstname: 'Jen', lastName: 'SomeLastName', sortOrder: 33},
   1: {firstname: 'ExampleFirstName', lastName: 'ExampleLastName', sortOrder: 12}
 ]
};

So I'd be trying to iterate through this to eventually find, in this case, the highest sortOrder of 33. Not necessarily the array index or the object containing it, just the number.

Thanks

about 4 years ago · Juan Pablo Isaza
3 answers
Answer question

0

(I had to slightly correct your input data: arrays don't include the index number as you're showing.)

Easiest to combine the two arrays in the object into one list and then use reduce to find the maximum:

const myObj = {
  people: [
    {
      firstname: 'Dave',
      lastName: 'Jones',
      sortOrder: 22
    },
    {
      firstname: 'Jane',
      lastName: 'Smith',
      sortOrder: 11
    }
  ],
  otherPeople: [
    {
      firstname: 'Jen',
      lastName: 'SomeLastName',
      sortOrder: 33
    },
    {
      firstname: 'ExampleFirstName',
      lastName: 'ExampleLastName',
      sortOrder: 12
    }
  ]
};


let allPeople = [...myObj.people, ...myObj.otherPeople];

let max = allPeople.reduce((maxSort, person) => {
  return Math.max(maxSort, person.sortOrder)
}, 0));

console.log(max)

about 4 years ago · Juan Pablo Isaza Report

0

You can order them by the highest sortOrder and then take the higher of the highest elements in each array:

const myObj = {
  people: [{
      firstname: 'Dave',
      lastName: 'Jones',
      sortOrder: 22
    },
    {
      firstname: 'Jane',
      lastName: 'Smith',
      sortOrder: 11
    }
  ],
  otherPeople: [{
      firstname: 'Jen',
      lastName: 'SomeLastName',
      sortOrder: 33
    },
    {
      firstname: 'ExampleFirstName',
      lastName: 'ExampleLastName',
      sortOrder: 12
    }
  ]
};
Object.values(myObj).forEach(peopleArray => {
  peopleArray.sort((a, b) => b.sortOrder - a.sortOrder)
})
let maxValue = Math.max(myObj.people[0].sortOrder, myObj.otherPeople[0].sortOrder)
console.log(maxValue)

about 4 years ago · Juan Pablo Isaza Report

0

  • Using Object#values get the list of arrays
  • Using Array#flat, convert the 2d array into one
  • Using Array#reduce, iterate over this list while updating a max

const myObj = {
  people: [ {firstname: 'Dave', lastName: 'Jones', sortOrder: 22}, {firstname: 'Jane', lastName: 'Smith', sortOrder: 11} ],
  otherPeople: [ {firstname: 'Jen', lastName: 'SomeLastName', sortOrder: 33}, {firstname: 'ExampleFirstName', lastName: 'ExampleLastName', sortOrder: 12} ]
};

const maxSortOrder = 
  Object.values(myObj)
  .flat()
  .reduce((max, { sortOrder = 0 }) => sortOrder > max ? sortOrder : max, 0);

console.log(maxSortOrder);

about 4 years ago · Juan Pablo Isaza Report
Answer question
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