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El archivo PHP y la función Javascript no capturan la identificación del div Html para mostrar el div oculto después de hacer clic en el botón Enviar

Tengo este div en index.php

 <div class="class" id="ScoreResult" style="display:none;">

y tengo esta función en seosystem/controller/youtubedata.php Intenté usar Js, no funcionó, así que quiero que cuando el usuario envíe el botón muestre el div para mostrar los datos

 if($_SERVER['REQUEST_METHOD'] == "GET" && isset($_GET['url']) && isset($_GET['submit'])){ /* echo "</br >" ; echo $input_Url_data . "Button clicked" ; */ $id_position = strstr($input_Url_data,"="); $id_position = trim($id_position, "=" ); // the alert works normally echo '<script> alert("heelo"); </script>'; // this part that trying to show the div doesn't work echo '<script type="text/JavaScript"> function showtable1() { document.getElementById( "ScoreResult").style.display = "block"; } showtable1(); </script>' ; echo "<style type=\"text/css\"> #ScoreResult {display:block;}</style>"; }

Esta es la forma de la entrada y el botón. No estoy seguro de si debería hacer la acción index.php o seosystem/controller/youtubedata.php

 <form class="d-flex justify-content-center " method="GET" action="index.php"> <div class="input-group "> <input type="text" class="form-control" name="url" placeholder="Enter Youtube Video URL" aria-label="Example text with button addon" aria-describedby="button-addon1"> <input class="btn" value="Analyze" name="submit" type="submit" id="button-addon1"></input> </div> </form>
about 4 years ago · Juan Pablo Isaza
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Agregue este código a su archivo index.php. Así es como muestra y oculta selectivamente el div ScoreResult. Espero que funcione para ti.

 <?php // This part should be added to the php section at the top of the page // Start by setting the $url_set status to 0 $url_set = 0; if (isset($_GET['url'])) { // Now we set the $url_set status to 1 $url_set = 1; } ?> <div class="class" id="ScoreResult"></div> <!--This section links the $url_set status to the code--> <input type="hidden" value="<?php echo $url_set ?>" id="url-status"> <!--Replace your JS section with this--> <script> function showtable1() { const url_status = document.querySelector('#url-status').value, dsp_status = url_status == 1 ? 'block' : 'none' document.getElementById("ScoreResult").style.display = dsp_status; } showtable1(); </script>
about 4 years ago · Juan Pablo Isaza Report
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