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Cómo filtrar una matriz según el valor de la propiedad o la existencia de propiedades

¿Cómo haría para filtrar una matriz en función de propiedades específicas dentro de ella?

Por ejemplo, si solo quisiera los objetos con la propiedad de season en ellos.

 [ { population: 121321313, location: 'American city in the East', }, { season: 'winter', population: 54646546, location: 'Canadian city in the East', }, { population: 6546467, location: 'American city in the West', }, { season: 'fall', population: 145313, location: 'American city in the South', }, { population: 12673, location: 'Canadian city2 in the East', }, { population: 141313, location: 'Canadian city in the South', }, { season: 'fall', population: 1264473, location: 'Canadian city4 in the East', }, { population: 12673, location: 'Canadian city6 in the South', }, ];
about 4 years ago · Juan Pablo Isaza
2 answers
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Está buscando Object#hasOwnProperty . Específicamente, está buscando filter su matriz solo a los elementos que tienen la season de propiedad que puede lograr de esta manera:

 const cities = [ { "population": 121321313, "location": "American city in the East" }, { "season": "winter", "population": 54646546, "location": "Canadian city in the East" }, { "population": 6546467,"location": "American city in the West"}, { "season": "fall", "population": 145313, "location": "American city in the South" }, { "population": 12673, "location": "Canadian city2 in the East" }, { "population": 141313, "location": "Canadian city in the South" }, { "season": "fall", "population": 1264473, "location": "Canadian city4 in the East" }, { "population": 12673, "location": "Canadian city6 in the South" } ]; const filteredCities = cities.filter(x => x.hasOwnProperty("season")); console.dir(filteredCities);


También podría usar el Reflect.has más moderno. Consulte Javascript object.hasOwnProperty() frente a Reflect.has() o ¿Cómo verifico si un objeto tiene una propiedad específica en JavaScript? para más información.

 const cities = [ { "population": 121321313, "location": "American city in the East" }, { "season": "winter", "population": 54646546, "location": "Canadian city in the East" }, { "population": 6546467,"location": "American city in the West"}, { "season": "fall", "population": 145313, "location": "American city in the South" }, { "population": 12673, "location": "Canadian city2 in the East" }, { "population": 141313, "location": "Canadian city in the South" }, { "season": "fall", "population": 1264473, "location": "Canadian city4 in the East" }, { "population": 12673, "location": "Canadian city6 in the South" } ]; const filteredCities = cities.filter(x => Reflect.has(x, "season")); console.dir(filteredCities);

about 4 years ago · Juan Pablo Isaza Report

0

puede usar la declaración: para ... de, para iterar objetos, luego busque sus elementos y empuje a la nueva matriz

 const list = [ { "population": 121321313, "location": "American city in the East" }, { "season": "winter", "population": 54646546, "location": "Canadian city in the East" }, { "population": 6546467, "location": "American city in the West" }, { "season": "fall", "population": 145313, "location": "American city in the South" }, { "population": 12673, "location": "Canadian city2 in the East" }, { "population": 141313, "location": "Canadian city in the South" }, { "season": "fall", "population": 1264473, "location": "Canadian city4 in the East" }, { "population": 12673, "location": "Canadian city6 in the South" } ]; let Newarr = []; for (const item of list) { if(Object.hasOwn(item, "season")) { Newarr.push(item); } } console.log(Newarr);

about 4 years ago · Juan Pablo Isaza Report
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