Business
Jobs
  • About Us
  • Solutions
    • Job Postings
      Post your job and receive qualified candidates in 48h.
    • Candidate Assessments
      500+ technical and psychological tests, plus anti-fraud.
    • Headhunting
      Tailor-made executive search from start to finish.
    • Payroll + EOR
      Payroll dispersal and EOR across 15+ LATAM countries.
  • Pricing
  • Jobs

0

243
Views
Cargue los contenidos de PHP solo después de cambiar una pestaña de navegación

Tengo 10 pestañas en mi proyecto, cada una de ellas obtendrá algunos valores de la API usando PHP.
Se tarda entre 10 y 15 segundos en cargar la página cada vez (ya que actualiza los valores de las 10 pestañas)

¿Cómo cargo contenido solo después de cambiar de pestaña ?

Cargue TAB1 al inicio , luego solo después de hacer clic en TAB2 o TAB3 y luego cargue su contenido, pero no los cargue al inicio

Ejemplo: https://jsfiddle.net/t52mwLoc/

 <div class="col-md-6"> <div class="card"> <div class="card-body"> <h4 class="card-title">Default Tab</h4> <!-- Nav tabs --> <ul class="nav nav-tabs" role="tablist"> <li class="nav-item"> <a class="nav-link active show" data-toggle="tab" href="#tab1" role="tab" aria-selected="true">TAB1</a> </li> <li class="nav-item"> <a class="nav-link" data-toggle="tab" href="#tab2" role="tab" aria-selected="false"> TAB2</a> </li> <li class="nav-item"> <a class="nav-link" data-toggle="tab" href="#tab3" role="tab" aria-selected="false"><span class="hidden-sm-up"> TAB3</a> </li> </ul> <!-- Tabs --> <div class="tab-content tabcontent-border"> <div class="tab-pane active show" id="tab1" role="tabpanel"> <div class="p-20"> Load this content... [TAB1] </div> </div> <div class="tab-pane p-20" id="tab2" role="tabpanel">some PHP... Load this ONLY after clicking [TAB2]</div> <div class="tab-pane p-20" id="tab3" role="tabpanel">some PHP... Load this ONLY after clicking [TAB3]</div> </div> </div> </div> </div> <script src="https://code.jquery.com/jquery-3.6.0.min.js"></script> <link rel="stylesheet" href="https://stackpath.bootstrapcdn.com/bootstrap/4.1.3/css/bootstrap.min.css"> <script src="https://stackpath.bootstrapcdn.com/bootstrap/4.1.3/js/bootstrap.min.js"></script>

about 4 years ago · Juan Pablo Isaza
1 answers
Answer question

0

Algo simple que puedes hacer es esto. ejemplo en vivo aquí

 <!DOCTYPE html> <head> <script src="https://ajax.googleapis.com/ajax/libs/jquery/3.5.1/jquery.min.js"></script> <script> function initialLoad(){ $('#loader').load("page1.php"); } </script> </head> <body onload="initialLoad()"> Click on buttons to load different pages <br/> <button style="margin-left: 20px" class="btn btn-primary" onclick="load(1)"> Page 1 </button> <button style="margin-left: 20px" class="btn btn-primary" onclick="load(2)"> Page 2 </button> <button style="margin-left: 20px" class="btn btn-primary" onclick="load(3)"> Page 3 </button> <button style="margin-left: 20px" class="btn btn-primary" onclick="load(4)"> Page 4 </button> <button style="margin-left: 20px" class="btn btn-primary" onclick="load(5)"> Page 5 </button><br/><br/> <div class="load" id="loader"> </div> <h3>You can check the network tab to see which page is getting loaded</h3> <script> function load(page){ var thePage = "page"+page+".php" $('#loader').load(thePage);//assuming u have page1.php page2.php like this } </script> </body> </html>

Para cualquier consulta comenta abajo.

about 4 years ago · Juan Pablo Isaza Report
Answer question
Find remote jobs

Discover the new way to find a job!

Top jobs
Top job categories
Business
Post vacancy Pricing Sales
Legal
Terms and conditions Privacy policy
© 2026 PeakU Inc. All Rights Reserved.
Andres GPT
Show me some job opportunities
There's an error!