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Call async function out side function

I have next code and sequence in which it runs is incorrect:

async function getItems(table) {
  return obj; // call 3, why it is called after module.exports and how to fix it
}

const {
var1,
var2
} = (async () => {
  await getItems('env-variables-feature'); // call 1
})();

exports = {
status: var1,
something: var2
};

module.exports = exports; // call 2

As I know await means we should wait until function execute

about 4 years ago · Juan Pablo Isaza
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