At the end I get numbers, how to convert it to array?
Example:
Input: 4, 5, 1, 2, 3, -2
Output: [(13, 9, 4, 3, 1, -2)];
function sumNumbers(numbersList) {
const data = numbersList.forEach((item, index) => {
const output = numbersList.reduce(
(acc, c, i) => (index !== i ? (acc += c) : c),
0
);
console.log(result);
return output;
});
return data;
}
sumNumbers([4, 5, 1, 2, 3, -2]);Consider replacing the Array.prototype.forEach with Array.prototype.map (since we want the value returned)
function sumNumbers(numbersList) {
const main = numbersList.map((item, index) => {
const result = numbersList.reduce(
(acc, c, i) => (index !== i ? (acc += c) : c),
0
);
return result;
});
return main;
}
console.log(sumNumbers([4, 5, 1, 2, 3, -2]))Explanation:
.forEach returns undefined (docs)
while .map returns "A new array with each element being the result of the callback function." (docs)
The response given by @tibebes-m, an other approach (which reduces complexity) is to iterate back the array backwards, and use only a reduce function (no map)
const sumNumbers = (list) => list
.reverse()
.reduce((acc, next, index) => {
acc.unshift(next + (acc[0] || 0));
return acc;
}, []);
console.log(sumNumbers([4, 5, 1, 2, 3, -2]));