I have a problem in reducing an object which contains array into a simple array. I have a backend which returns a list of dogs and their price. The way the api returns the data, seems really difficult to work with and I am struggling to convert the object into an array. I have tried turning into an array and reducing it.
Here is an example - I want to convert the following object:
const a = {
dogs: [{
"id": "dog1",
"priceRange": [
"low",
"high"
],
"vaccinated": true,
},
{
"id": "dog2",
"priceRange": [
"low",
"high"
],
"vaccinated": false,
}
],
"cost": [{
"id": "low",
"cost": 200,
},
{
"id": "mid",
"cost": 400,
},
{
"id": "high",
"cost": 600,
}
]
};
into this array:
const reducedArray = [{
"id": "dog1",
"priceRange": [{
"id": "low",
"cost": 200,
},
{
"id": "high",
"cost": 600,
}
],
"vaccinated": true,
},
{
"id": "dog2",
"priceRange": [{
"id": "low",
"cost": 200,
},
{
"id": "high",
"cost": 600,
}
],
"vaccinated": false,
}
]
I am not sure
You need to iterate over your a.dogs array first and within each iteration, also iterate over the priceRange array and find its corresponding value inside the a.cost array and return that instead of the string low or high.
a.dogs.map(dog => ({
...dog,
priceRange: dog.priceRange.map(priceRange => a.cost.find(cost => cost.id === priceRange))
}))
Array#reduce, iterate over a.cost while updating a Map where the key is the id and value is the objectArray#map, iterate over a.dogs and set the priceRannge items from the Map using another Array#map iteraionconst a = {
"dogs": [ { "id": "dog1", "priceRange": [ "low", "high" ], "vaccinated": true }, { "id": "dog2", "priceRange": [ "low", "high" ], "vaccinated": false } ],
"cost": [ { "id": "low", "cost": 200 }, { "id": "mid", "cost": 400 }, { "id": "high", "cost": 600 } ]
};
const costMap = a.cost.reduce((map, cost) =>
map.set(cost.id, cost)
, new Map);
const reducedArray = a.dogs.map(dog => ({
...dog,
priceRange: dog.priceRange.map(range => {
const { id, cost } = costMap.get(range) || {};
return { id, cost};
})
}));
console.log(reducedArray);