I developed a logic for the above problem but i couldnt get the desired result.
function thirdOccurence(string){
var count = 0;
var i=0;
var result = 0;
while(i<string.length){
if(string[i]=='e' && string[i+1]=='f' && string[i+2]=='g')
{
count = count+1;
i+3;
if(count==3)
{
result = i+1;
break;
}
}
else
i++;
}
}*
here the string is the input - abcefgacefgabcceftyefghjklop -output should be 20 since we need to find position. I have a working code but with a different logic. But i need to know why this is not working.
The problem was with the line where you increment the i variable by 3: i += 3. This meant you jumped 3 indexes forward, before the final condition if(count==3). But if you increment i by 3 after this final condition - everything works as expected :)
function thirdOccurence(string) {
var count = 0;
var i = 0;
var result = 0;
while (i < string.length) {
if (string[i] === "e" && string[i + 1] === "f" && string[i + 2] === "g") {
count += 1;
if (count === 3) {
result = i + 1;
break;
}
i += 3;
} else {
i++;
}
}
return result
}
console.log('result should be 20:', thirdOccurence('abcefgacefgabcceftyefghjklop'))