Hey guys I m trying to loop over the array of numbers, and what i want my function to do is whenever it is position of a number in array is EVEN number I want a program to return me 'Yan' word in stead of number. but when the position of a number is ODD number i want it to return just a number.
But for some reason in the middle of the array I am getting 'Yan' word instead of getting a number.
const valid1 = [4, 5, 3, 9, 6, 7, 7, 9, 0, 8, 0, 1, 6, 8, 0, 8]
const reversValid1 = valid1.reverse()
const myArray = []
const validateCard = (arr) =>{
for(let i = 0; i < arr.length; i++){
if(arr.indexOf(reversValid1[i])%2 == 1){
console.log('Yan')
}
else{
console.log(arr[i])
}
}
}
validateCard(reversValid1)I m getting the following response:
8 Yan 8 Yan 1 Yan 8 Yan 9 Yan Yan Yan 9 Yan 5 Yan
You can see i m getting 3 Yan consecutively.
Why instead of use indexOf don't use directly i ?
const valid1 = [4, 5, 3, 9, 6, 7, 7, 9, 0, 8, 0, 1, 6, 8, 0, 8]
const reversValid1 = valid1.reverse()
const myArray = []
const validateCard = (arr) => {
for (let i = 0; i < arr.length; i++) {
if (i % 2 == 1) {
console.log('Yan')
} else {
console.log(arr[i])
}
}
}
validateCard(reversValid1)The problem is indexOf will find multiple index of same number.
Example:
const valid1 = [4, 5, 3, 9, 6, 7, 7, 9, 0, 8, 0, 1, 6, 8, 0, 8]
const reversValid1 = valid1.reverse()
for (let i = 0; i < reversValid1.length; i++) {
console.log(reversValid1[i], reversValid1.indexOf(reversValid1[i]))
}As you can see the same number have same index instead of index of array.
You can use Array.forEach:
const valid1 = [4, 5, 3, 9, 6, 7, 7, 9, 0, 8, 0, 1, 6, 8, 0, 8];
const reversValid1 = valid1.slice().reverse();
const validateCard = (arr) => {
arr.forEach((v,i)=>{
if (i%2 == 0) {
console.log('Yan');
} else {
console.log(v);
}
});
};
validateCard(reversValid1);This might be what you want:
const valid1 = [4, 5, 3, 9, 6, 7, 7, 9, 0, 8, 0, 1, 6, 8, 0, 8];
const reversValid1 = valid1.reverse();
const myArray = []
const validateCard = (arr) => {
for (let i = 0; i < arr.length; i++) {
if (arr[i] % 2 === 0) {
console.log('Yan');
}
else {
console.log(arr[i]);
}
}
}
validateCard(reversValid1);Or this:
const valid1 = [4, 5, 3, 9, 6, 7, 7, 9, 0, 8, 0, 1, 6, 8, 0, 8];
const reversValid1 = valid1.reverse();
const validateCard2 = (arr) => {
for (let i = 0; i < arr.length; i++) {
if (i % 2 === 0) {
console.log('Yan');
}
else {
console.log(arr[i]);
}
}
}
validateCard2(reversValid1);