Business
Jobs
  • About Us
  • Solutions
    • Job Postings
      Post your job and receive qualified candidates in 48h.
    • Candidate Assessments
      500+ technical and psychological tests, plus anti-fraud.
    • Headhunting
      Tailor-made executive search from start to finish.
    • Payroll + EOR
      Payroll dispersal and EOR across 15+ LATAM countries.
  • Pricing
  • Jobs

0

91
Views
amazon s3.upload is taking time

I am trying to upload file to s3, before that I am altering the name of the file. Now I am accepting 2 files from request form-data object, renaming the filename, and uploading the file to s3. And end of the task I need to return the renamed file list which is uploaded successfully.

I am using S3.upload() function. But the problem is, the variable which is assigned as empty array initially, that will contain the renamed file list. But the array is returning empty response. The s3.upload() is taking much time. is there any probable solution where I can store the file name if upload is successful and return those names in response.

Please help me to fix this. The code looks like this,

      if (formObject.files.document && formObject.files.document.length > 0) {
        const circleCode = formObject.fields.circleCode[0];
        let collectedKeysFromAwsResponse = [];
        formObject.files.document.forEach(e => {
          const extractFileExtension = ".pdf";
          if (_.has(FILE_EXTENSIONS_INCLUDED, _.lowerCase(extractFileExtension))) {
            console.log(e);
            //change the filename
            const originalFileNameCleaned = "cleaning name logic";
            const _id = mongoose.Types.ObjectId();
            const s3FileName = "s3-filename-convension;
            console.log(e.path, "", s3FileName);
            const awsResponse = new File().uploadFileOnS3(e.path, s3FileName);
            if(e.hasOwnProperty('ETag')) {
              collectedKeysFromAwsResponse.push(awsResponse.key.split("/")[1])
            }
          }
        });
      };
about 4 years ago · Juan Pablo Isaza
2 answers
Answer question

0

use await s3.upload(params).promise(); is the solution.

about 4 years ago · Juan Pablo Isaza Report

0

Use the latest code - which is AWS SDK for JavaScript V3. Here is the code you should be using

// Import required AWS SDK clients and commands for Node.js.
import { PutObjectCommand } from "@aws-sdk/client-s3";
import { s3Client } from "./libs/s3Client.js"; // Helper function that creates Amazon S3 service client module.
import {path} from "path";
import {fs} from "fs";

const file = "OBJECT_PATH_AND_NAME"; // Path to and name of object. For example '../myFiles/index.js'.
const fileStream = fs.createReadStream(file);

// Set the parameters
export const uploadParams = {
  Bucket: "BUCKET_NAME",
  // Add the required 'Key' parameter using the 'path' module.
  Key: path.basename(file),
  // Add the required 'Body' parameter
  Body: fileStream,
};


// Upload file to specified bucket.
export const run = async () => {
  try {
    const data = await s3Client.send(new PutObjectCommand(uploadParams));
    console.log("Success", data);
    return data; // For unit tests.
  } catch (err) {
    console.log("Error", err);
  }
};
run();

More details can be found in the AWS JavaScript V3 DEV Guide.

about 4 years ago · Juan Pablo Isaza Report
Answer question
Find remote jobs

Discover the new way to find a job!

Top jobs
Top job categories
Business
Post vacancy Pricing Sales
Legal
Terms and conditions Privacy policy
© 2026 PeakU Inc. All Rights Reserved.
Andres GPT
Show me some job opportunities
There's an error!