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Compara dos matrices de objetos; Si el segundo objeto contiene la misma clave/valor que el primero, devuelva el segundo; si no, agregue la clave/valor del primero

Considere lo siguiente: Tenemos dos arreglos, cada uno con un objeto.

 let users: [ { "id": "some#" "name": "some name", "data": "somedata" } ], let products: [ { "product": "some#" "name": "abc", }, ]

Esencialmente, compare ambos objetos, si el segundo objeto tiene la misma propiedad que el primero, conserve la segunda propiedad y el valor si no agrega la propiedad/valor del primero.

Entonces la salida es:

 { "id": "some#", "name": "abc", "data": "somedata" }
about 4 years ago · Juan Pablo Isaza
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0

Prueba esto:

 if (!(users[0].name === products[0].name)) { product[0].data = users[0].data }
about 4 years ago · Juan Pablo Isaza Report

0

Con el siguiente código, para los datos que ha proporcionado, puede obtener el resultado que está buscando:

 let users = [ { id: "some#", name: "some name", data: "somedata" } ]; let products = [ { product: "some#", name: "abc" } ]; for (key in users[0]) { if (products[0][key]) { users[0][key] = products[0][key]; } else { continue; } } console.log(users);

about 4 years ago · Juan Pablo Isaza Report
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