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por qué esta función no devuelve los datos. muestra solo indefinido mientras lo imprime

Solo traté de hacer una función que tomará archivos CSV y devolverá datos JSON. cuando consuele los datos, funcionará bien, pero cuando intenté devolver los mismos datos, devolverá undefined .

 var fs = require('fs'); //sorting the json... function compareStrings(a, b) { a = a.toLowerCase(); b = b.toLowerCase(); return (a < b) ? -1 : (a > b) ? 1 : 0; } //reding csv and converting it into json.......... var csv_to_json = ()=>{ fs.readFile('./Data/book.csv',(err,data)=>{ let jsonData = []; var content = data.toString().split('\n').join().split('\r'); var key = content[0].split(';'); content.shift(); content.forEach((item)=>{ var temp = item.replace(",").split(';'); var data = {} for(var i=0;i<key.length;i++){ data[key[i]] = temp[i] } jsonData.push(data); }) jsonData.sort(function(a, b) { return compareStrings(a.title, b.title); }) // console.log is working fine but when I tried to return the same data it won't work properly // console.log(jsonData); return jsonData; }) } console.log(csv_to_json())
about 4 years ago · Juan Pablo Isaza
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Porque usa una función de devolución de llamada y cuando usa la función de devolución de llamada, el código se ejecuta de forma asíncrona

Te sugiero que leas este documento .

Tienes que cambiar el código así:

 var fs = require('fs'); //sorting the json... function compareStrings(a, b) { a = a.toLowerCase(); b = b.toLowerCase(); return (a < b) ? -1 : (a > b) ? 1 : 0; } //reding csv and converting it into json.......... var csv_to_json = (callback)=>{ fs.readFile('./Data/book.csv',(err,data)=>{ let jsonData = []; var content = data.toString().split('\n').join().split('\r'); var key = content[0].split(';'); content.shift(); content.forEach((item)=>{ var temp = item.replace(",").split(';'); var data = {} for(var i=0;i<key.length;i++){ data[key[i]] = temp[i] } jsonData.push(data); }) jsonData.sort(function(a, b) { return compareStrings(a.title, b.title); }) // console.log is working fine but when I tried to return the same data it won't work properly // console.log(jsonData); callback(null, jsonData); }) } csv_to_json((error, data) => { console.log(data); })
about 4 years ago · Juan Pablo Isaza Report
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