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Using only Record in interface instead of dynamic keys in TypeScript

in type i can write both ways:

  1. type someType = {[key: string]: any}
  2. type someType = Record<string, any>

I want to do the same with interface bu instead of: interface someInter {[key: string]: any} i want to be able to do something like: interface someInter Record<string, any>..

Is it possible at all? in any way?

about 4 years ago · Juan Pablo Isaza
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