I'm working with an angular project. I have a string like below and i sorted out all the special characters using regular expressions. Now, I want the first 2 strings to be in suare brackets and the second two in another square bracket like coordinates, and the output should be like below. Please help me achieve the functionality.
test: any = "((-1.23568 75.87956), (-1.75682 22.87694))"
My ts code be like:
hello()
{
this.new = ( this.test.replace(/[^\d. -]/g, ''));
this.newarr = this.new.split(" ");
const result = this.newarr.filter(e => e);
}
and my final output in result array is like:
["-1.23568", "75.87956", "-1.75682", "22.87694"]
Desired output
[ ["-1.23568", "75.87956"], ["-1.75682", "22.87694"] ]
Another approach would be to use String.match() to get each group of coordinates, then Array.map() and String.split() to divide into pairs.
let test = "((-1.23568 75.87956), (-1.75682 22.87694))";
const result = test.match(/[\d.-]+\s[\d.-]+/g).map(s => s.split(/\s/));
console.log('Result:', result);.as-console-wrapper { max-height: 100% !important; top: 0; }You can avoid some complex regex logic and just, once you have:
const [a1, a2, b1, b2] = ["-1.23568", "75.87956", "-1.75682", "22.87694"]
const result = [[a1, a2], [b1, b2]]
Or if there are more than two pairs:
const array = ["-1.23568", "75.87956", "-1.75682", "22.87694", "-1.33343", "3.34432"]
const result = [];
for(let i = 0; i < array.length; i+=2) {
result.push(array.slice(i, i+2))
}
For example you can use Array.prototype.splice(). This function can give you such 'portions' for your new array:
pairs.push(initialArr.splice(0, 2))
Juts loop through your initial array initialArr.length/2 times.
EDIT: Or maybe you can update your replacing logic for getting not just number after number but pairs (for example '-1.23568 75.87956,-1.75682 22.87694') and then just split it twice.
split(',') --> ['-1.23568 75.87956', '-1.75682 22.87694']
and then loop and
split(' ')