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How do I conditionally add attributes to React components?

Is there a way to only add attributes to a React component if a certain condition is met?

I'm supposed to add required and readOnly attributes to form elements based on an Ajax call after render, but I can't see how to solve this since readOnly="false" is not the same as omitting the attribute completely.

The example below should explain what I want, but it doesn't work.

(Parse Error: Unexpected identifier)

function MyInput({isRequired}) {
  return <input classname="foo" {isRequired ? "required" : ""} />
}
over 4 years ago · Santiago Trujillo
3 answers
Answer question

0

Apparently, for certain attributes, React is intelligent enough to omit the attribute if the value you pass to it is not truthy. For example:

const InputComponent = function() {
    const required = true;
    const disabled = false;

    return (
        <input type="text" disabled={disabled} required={required} />
    );
}

will result in:

<input type="text" required>

Update: if anyone is curious as to how/why this happens, you can find details in ReactDOM's source code, specifically at lines 30 and 167 of the DOMProperty.js file.

over 4 years ago · Santiago Trujillo Report

0

juandemarco's answer is usually correct, but here is another option.

Build an object how you like:

var inputProps = {
  value: 'foo',
  onChange: this.handleChange
};

if (condition)
  inputProps.disabled = true;

Render with spread, optionally passing other props also.

<input
    value="this is overridden by inputProps"
    {...inputProps}
    onChange={overridesInputProps}
 />
over 4 years ago · Santiago Trujillo Report

0

Here is an example of using Bootstrap's Button via React-Bootstrap (version 0.32.4):

var condition = true;

return (
  <Button {...(condition ? {bsStyle: 'success'} : {})} />
);

Depending on the condition, either {bsStyle: 'success'} or {} will be returned. The spread operator will then spread the properties of the returned object to Button component. In the falsy case, since no properties exist on the returned object, nothing will be passed to the component.


An alternative way based on Andy Polhill's comment:

var condition = true;

return (
  <Button bsStyle={condition ? 'success' : undefined} />
);

The only small difference is that in the second example the inner component <Button/>'s props object will have a key bsStyle with a value of undefined.

over 4 years ago · Santiago Trujillo Report
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