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Si else está en la matriz, pero solo ejecuta la declaración else una vez, no cada vez que el resultado es falso

Tengo una matriz y un nombre.

 var name = "Karen" var arr = [ "Karen", "Ronald", "Mcdonald" ]; // Code here

Quiero verificar si el name está indexado en arr .
Si es entonces console.log(true) , pero si no, solo quiero console.log(false); una vez.
Estoy registrando falso cada vez que el nombre no coincide, ese es mi problema.

about 4 years ago · Juan Pablo Isaza
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Parece bastante simple.

 const name = "Karen" var arr = [ "Karen", "Ronald", "Mcdonald" ]; if (arr.indexOf(name) > -1) { console.log(true); } else { console.log(false); }

O Array.prototype.some :

 var name = "Karen"; var arr = [ "Karen", "Ronald", "Mcdonald" ]; console.log(arr.some(n => n == name))

Referencia MDN

about 4 years ago · Juan Pablo Isaza Report
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