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includes() not working in all browsers

right here is a block of my code. It works perfect in fireFox and Chrome. But not in IE. I get the error "Object doesn't support property or method 'includes'"

function rightTreeSwapfunc2() {
    if ($(".right-tree").css("background-image").includes("stage1") == true) {
        $(".right-tree").css({
            backgroundImage: "url(/plant-breeding/img/scenes/plant-breeding/stage5.jpg)"
        })
    } else {
        $(".right-tree").css({
            backgroundImage: "url(/plant-breeding/img/scenes/plant-breeding/stage3.jpg)"
        })
    }
}

I could change it up a bit and use vanilla JS and do:

document.getElementById("right-tree").classList.contains

But I would rather see if there is a way to get it to work in IE before changing the JS and editing the HTML and CSS.

over 4 years ago · Santiago Trujillo
3 answers
Answer question

0

If you look at the documentation of includes(), most of the browsers don't support this property.

You can use widely supported indexOf() after converting the property to string using toString():

if ($(".right-tree").css("background-image").indexOf("stage1") > -1) {
//                                           ^^^^^^^^^^^^^^^^^^^^^^

You can also use the polyfill from MDN.

if (!String.prototype.includes) {
    String.prototype.includes = function() {
        'use strict';
        return String.prototype.indexOf.apply(this, arguments) !== -1;
    };
}
over 4 years ago · Santiago Trujillo Report

0

IE11 does implement String.prototype.includes so why not using the official Polyfill?

Source: polyfill source

  if (!String.prototype.includes) {
    String.prototype.includes = function(search, start) {
      if (typeof start !== 'number') {
        start = 0;
      }

      if (start + search.length > this.length) {
        return false;
      } else {
        return this.indexOf(search, start) !== -1;
      }
    };
  }
over 4 years ago · Santiago Trujillo Report

0

In my case i found better to use "string.search".

var str = "Some very very very long string";
var n = str.search("very");

In case it would be helpful for someone.

over 4 years ago · Santiago Trujillo Report
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