Business
Jobs
  • About Us
  • Solutions
    • Job Postings
      Post your job and receive qualified candidates in 48h.
    • Candidate Assessments
      500+ technical and psychological tests, plus anti-fraud.
    • Headhunting
      Tailor-made executive search from start to finish.
    • Payroll + EOR
      Payroll dispersal and EOR across 15+ LATAM countries.
  • Pricing
  • Jobs

0

1.3K
Views
Get full file path in Node.js

I have an application which uploads csv file into a particular folder, say, "uploads". Now I want to get the full path of that csv file, for example, D:\MyNodeApp\uploads\Test.csv.

How do I get the file location in Node.js? I used multer to upload file.

over 4 years ago · Santiago Trujillo
3 answers
Answer question

0

var path = require("path");
var absolutePath = path.resolve("Relative file path");

You dir structure for example:

C:->WebServer->Public->Uploads->MyFile.csv

and your working directory would be Public for example, path.resolve would be like that.

path.resolve("./Uploads/MyFile.csv");

POSIX home/WebServer/Public/Uploads/MyFile.csv
WINDOWS C:\WebServer\Public\Uploads\MyFile.csv

this solution is multiplatform and allows your application to work on both windows and posix machines.

over 4 years ago · Santiago Trujillo Report

0

Get all files from folder and print each file description.

const path = require( "path" );
const fs = require( 'fs' );
const log = console.log;
const folder = './';

fs.readdirSync( folder ).forEach( file => {
   
   const extname = path.extname( file );
   const filename = path.basename( file, extname );
   const absolutePath = path.resolve( folder, file );

   log( "File : ", file );
   log( "filename : ", filename );
   log( "extname : ", extname );
   log( "absolutePath : ", absolutePath);

});
over 4 years ago · Santiago Trujillo Report

0

Assuming you are using multer with express, try this in your controller method:

var path = require('path');

//gets your app's root path
var root = path.dirname(require.main.filename)

// joins uploaded file path with root. replace filename with your input field name
var absolutePath = path.join(root,req.files['filename'].path) 
over 4 years ago · Santiago Trujillo Report
Answer question
Find remote jobs

Discover the new way to find a job!

Top jobs
Top job categories
Business
Post vacancy Pricing Sales
Legal
Terms and conditions Privacy policy
© 2026 PeakU Inc. All Rights Reserved.
Andres GPT
Show me some job opportunities
There's an error!