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¿Cómo se puede escribir un reductor mixin funcional?

Estoy aprendiendo mecanografiado y tengo problemas para descubrir cómo escribir correctamente una función reductora que reduzca los mixins funcionales.

Dados dos mixins funcionales como:

 type FooComposable = { foo: string; }; const withFoo = (composable): FooComposable => { composable.foo = 'foo'; return composable; }; type BarComposable = { bar: string; }; const withBar = (composable): BarComposable => { composable.bar = 'bar'; return composable; };

Tengo una función reductora que reducirá todos los mixins funcionales provistos:

 const reduce(...fns) = fns.reduce((acc, fn) => fn(acc), {})); reduce(withFoo); // -> { foo: 'foo' } reduce(withBar); // -> { bar: 'bar' } reduce(withFoo, withBar); // -> { foo: 'foo', bar: 'bar' }

¿Cómo puedo agregar tipos a la función reduce() (y mixins funcionales) de modo que un componible reducido resultante tenga inferencias de tipo esperadas?

 type FooComposable = { foo: string; }; const withFoo = <T extends FooComposable>(composable: T): FooComposable => { composable.foo = 'foo'; return composable; }; type BarComposable = { bar: string; }; const withBar = <T extends BarComposable>(composable: T): BarComposable => { composable.bar = 'bar'; return composable; }; type FunctionalMixin<T extends {}> = (composable: T) => T; const reduce = <T extends {}>(...fns: FunctionalMixin<T>[]): T => fns.reduce((acc, fn) => fn(acc), {}); /* Type '{}' is not assignable to type 'T'. '{}' is assignable to the constraint of type 'T', but 'T' could be instantiated with a different subtype of constraint '{}'. */ reduce<FooComposable & BarComposable>(withFoo, withBar); // -> { foo: 'foo', bar: 'bar' } /* Argument of type '<T extends FooComposable>(composable: T) => FooComposable' is not assignable to parameter of type 'FunctionalMixin<FooComposable & BarComposable>'. Type 'FooComposable' is not assignable to type 'FooComposable & BarComposable'. Property 'bar' is missing in type 'FooComposable' but required in type 'BarComposable'. */
about 4 years ago · Juan Pablo Isaza
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¿Cómo puedo agregar tipos a la función reduce() (y mixins funcionales) de modo que un componible reducido resultante tenga inferencias de tipo esperadas?

En el siguiente ejemplo, el result tiene el tipo Foo & Bar correctamente inferido.

Patio de juegos

 type Foo = { foo: string; }; const withFoo: Mixin<Foo> = (a) => ({ ...a, foo: 'foo' }); type Bar = { bar: string; }; const withBar: Mixin<Bar> = (a) => ({ ...a, bar: 'bar' }); type Mixin<B> = <A extends object>(a: A) => A & B; type Reduce<A extends object, T extends unknown[]> = T extends [] ? A : T extends [Mixin<infer B>, ...infer C] ? Reduce<A & B, C> : never; const reduce = <T extends Mixin<unknown>[]>(...fns: T): Reduce<{}, T> => fns.reduce((a, fn) => fn(a), {}) as Reduce<{}, T>; const result = reduce(withFoo, withBar);
about 4 years ago · Juan Pablo Isaza Report
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