Part of an exercise I am to create a function called zip. It takes two arrays of equal length of elements and then separates them in two arrays with elements of equal indexes. I know there are other solutions using the map function but I am trying to figure out if there is another solution for this. So far I have this:
function zip(arr1, arr2) {
let pairArr = [];
for(var i = 0; i < arr1.length; i++) {
if(arr1.length === arr2.length){
let pairs = [arr1[i],arr2[i]];
pairArr.push(pairs);
} return pairArr;
}
}
This returns just one array with the first indexes of two arrays.
[1, 2, 3, 4] [1, 2, 3, 4]
returns [1, 1]. I need it to return [1, 1] [2, 2] [3, 3] [4, 4].
Thank you.
You are putting the return inside the loop. You should add it outside the loop. For example:
function zip(arr1, arr2) {
let pairArr = [];
for(var i = 0; i < arr1.length; i++){
if (arr1.length === arr2.length){
let pairs = [arr1[i],arr2[i]];
pairArr.push(pairs);
}
}
return pairArr;
}
console.log(zip([1, 2, 3, 4], [1, 2, 3, 4] ));Thank you everyone your input. I didn't realize that I had my return in the loop. I did solve it. This is what I have for the zip function.
function zip(arr1, arr2) {
let pairArr = [];
for(var i = 0; i < arr1.length; i++){
if (arr1.length === arr2.length){
pairArr[i] = [arr1[i],arr2[i]];
}
}return pairArr;
}
Here is a better implementation of python-style zip in JavaScript, which can take an arbitrary number of arrays as arguments and returns a result as long as the shortest parameter.
const zip = (...arrays) => {
const length = Math.min(...arrays.map(a => a.length));
return [...Array(length).keys()].map(i => arrays.map(a => a[i]));
}