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Converting AbstractComponent in TypeScript when using ForwardRef

I have many components that use forward refs built in Flow:

const ComponentWithRef: AbstractComponent<Props, HTMLInputElement> = forwardRef<
  Props,
  HTMLInputElement,
>(function Component(props: Props, ref): Node {


  const innerRef = useRef(null);

  useImperativeHandle(ref, () => innerRef.current);

  return <div>MyComponent</div> 
})

Im trying to convert this codebase to Typescript but AbstractComponent is not part of Typescript.

How do I handle converting Flow's React.AbstractComponent into something Typescript can support:

enter image description here

about 4 years ago · Juan Pablo Isaza
1 answers
Answer question

0

I think you just need to get rid of AbstractComponent type. Consider this example:

import React, { forwardRef, useRef, useImperativeHandle, ForwardedRef } from 'react'

type Props = {}


// React.ForwardRefExoticComponent<HTMLInputElement & React.RefAttributes<Props>>
const ComponentWithRef =
  forwardRef<
    Props,
    HTMLInputElement
  >((props: Props, ref) => {
    const innerRef = useRef(null);

    useImperativeHandle(ref, () => ({
      greet: () => 'Hello Batman :)'
    }));

    return <div ref={innerRef}>MyComponent</div>
  })

Playground

TypeScript is able to infer that ComponentWithRef is ForwardRefExoticComponent

Here you can find other forwardRef question

about 4 years ago · Juan Pablo Isaza Report
Answer question
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