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Ordenar matriz para obtener el más cercano desde hoy primero

Tengo una matriz como esta:

 array = [ { "title": "a", "date": "2021-10-25T18:00:00.000" }, { "title": "b", "date": "2021-10-20T18:00:00.000" }, { "title": "b", "date": "2021-10-28T18:00:00.000" }, { "title": "b", "date": "2021-10-30T18:00:00.000" }, { "title": "b", "date": "2021-10-26T18:00:00.000" } ]

Y primero quiero ordenarlo con el objeto más cercano de hoy. Intento ordenar pero creo que no tengo el buen método para hacer esto.

Esto es lo que probé:

 array.sort((a, b) => { return (new Date(b.battle_start) > new Date()) - (new Date(a.battle_start) < new Date()) })

Y esto es lo que quiero

 array = [ { "title": "b", "date": "2021-10-26T18:00:00.000" }, { "title": "a", "date": "2021-10-25T18:00:00.000" }, { "title": "b", "date": "2021-10-28T18:00:00.000" }, { "title": "b", "date": "2021-10-30T18:00:00.000" }, { "title": "b", "date": "2021-10-20T18:00:00.000" } ]
about 4 years ago · Juan Pablo Isaza
2 answers
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0

Su código se puede adaptar para usar Math.abs , de modo que la distancia al pasado o al futuro se considerará de la misma manera:

 const array = [{"title": "a","date": "2021-10-25T18:00:00.000"},{"title": "b","date": "2021-10-20T18:00:00.000"},{"title": "b","date": "2021-10-28T18:00:00.000"},{"title": "b","date": "2021-10-30T18:00:00.000"},{"title": "b","date": "2021-10-26T18:00:00.000"}]; let now = Date.now(); array.sort((a,b) => Math.abs(Date.parse(a.date) - now) - Math.abs(Date.parse(b.date) - now) ); console.log(array);

about 4 years ago · Juan Pablo Isaza Report

0

Debería poder hacerlo a través de:

 array.sort((a, b) => { return (Math.abs(new Date(a.battle_start) - new Date())) - Math.abs((new Date(b.battle_start) - new Date())) })

Lo que desea comparar es la distancia entre "ahora" y la fecha objetivo.

about 4 years ago · Juan Pablo Isaza Report
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