I am currently trying out Django. I use the namespace argument in one of my include()s in urls.py. When I run the server and try to browse,
I get this error.
File "C:\Users\User\AppData\Local\Programs\Python\Python36-32\lib\site-packages\django\urls\conf.py", line 39, in include
'Specifying a namespace in include() without providing an app_name '
django.core.exceptions.ImproperlyConfigured: Specifying a namespace in include() without providing an app_name is not supported. Set the app_name attribute in the included module, or pass a 2-tuple containing the list of patterns and app_name instead.
These are my urls.py files:
#project/urls.py
from django.conf.urls import include, url
from django.contrib import admin
urlpatterns = [
url(r'^reviews/', include('reviews.urls', namespace='reviews')),
url(r'^admin/', include(admin.site.urls)),
]
and
#app/urls.py
from django.conf.urls import url
from . import views
urlpatterns = [
# ex: /
url(r'^$', views.review_list, name='review_list'),
# ex: /review/5/
url(r'^review/(?P<review_id>[0-9]+)/$', views.review_detail, name='review_detail'),
# ex: /wine/
url(r'^wine$', views.wine_list, name='wine_list'),
# ex: /wine/5/
url(r'^wine/(?P<wine_id>[0-9]+)/$', views.wine_detail, name='wine_detail'),
]
What do I pass the app_name as stated in the error message?
You should set the app_name in the urls file you are including
# reviews/urls.py <-- i.e. in your app's urls.py
app_name = 'reviews'
Then you can include it the way you are doing it.
Also, it might be worth noting what Django docs say here https://docs.djangoproject.com/en/1.11/ref/urls/#include :
Deprecated since version 1.9: Support for the app_name argument is deprecated and will be removed in Django 2.0. Specify the app_name as explained in URL namespaces and included URLconfs instead.
( https://docs.djangoproject.com/en/1.11/topics/http/urls/#namespaces-and-include )
Django 2.0 you should specify app_name in your urls.py, is not necessary to specify app_name argument on include.
Main Url file.
from django.contrib import admin
from django.urls import path, include
urlpatterns = [
path('', include('apps.main.urls')),
path('admin/', admin.site.urls),
]
Included Url.
from django.urls import path
from . import views
app_name = 'main_app'
urlpatterns = [
path('', views.index, name='index'),
]
Then use use in template as
<a href="{% url main_app:index' %}"> link </a>
More details: https://code.djangoproject.com/ticket/28691 Django 2.0 Docs