let array = [1, [2, 3, [4, 5, ["six", "seven", 6666, [8, 9, [10]]]]]]
//1.find last element
//2. index way like in **console.log(array[1][2][2][3][2][0]** but should print
// [1][2][2][3][2][0] or 1,2,2,3,2,0
in this function i find last element now i can't find the 2nd question (it should be recursive function )
function findLastElement (arr){
for (let element of arr ){
if(typeof element === "object"){
findLastElement(element)
console.log(element)
}
}
}
findLastElement(array)
You can use a recursive function to always take the last index, and continue if the the last item is an array as well:
const getLessIndexes = arr => {
const last = arr.length - 1
return [
last,
...Array.isArray(arr[last])
? getLessIndexes(arr[last])
: []
]
}
const array = [1, [2, 3, [4, 5, ["six", "seven", 6666, [8, 9, [10]]]]]]
const result = getLessIndexes(array)
console.log(result)let array = [1, [2, 3, [4, 5, ["six", "seven", 6666, [8, 9, [10]]]]]];
function findLastElement (arr){
for (let [index, element] of arr.entries() ){
if(typeof element === "object"){
findLastElement(element)
console.log(element)
console.log(index)
}
}
}
console.log( findLastElement(array) )You can use Array.entries()
function findLastElement (arr){
for (let [index, element] of arr.entries() ){
if(typeof element === "object"){
findLastElement(element)
console.log(element)
console.log(index)
}
}
}