function reverse1(str) {
let r = "";
for (let i = str.length - 1; i >= 0; i--) {
r += str[i];
}
return r;
}
console.log(reverse1("I like this program very much"));
output: // hcum yrev margorp siht ekil I
but expected output: I ekil siht margorp yrev hcum
please can any one answer this....???
Traverse the original string and reverse the individual words.
function reverseUtil(str) {
let r = "";
for (let i = str.length - 1; i >=0; i--) {
r += str[i];
}
return r;
}
function reverse1(str) {
let r = "", tmp = "";
for (let i = 0; i < str.length; i++) {
if (str[i] == ' ') {
r += reverseUtil(tmp) + ' ';
tmp = "";
} else tmp += str[i];
}
// last word
r += reverseUtil(tmp);
return r;
}
console.log(reverse1("I like this program very much"));You are reversing the whole string. If you want to use a single function and assuming the string contains spaces only, you can loop through every character of the string.
If you encounter a space, you can append that to the result. If you encounter another character, you can prepend that to a temporary string to build a reversed version of the word.
Then append the reversed version of word to the result when the next character is either a space or when it is the last character in the iteration.
function reverse1(str) {
let result = "", tmp = "";
for (let i = 0; i < str.length; i++) {
if (str[i] === ' ') {
result += ' '; continue;
}
tmp = str[i] + tmp;
if (str[i + 1] === undefined || str[i + 1] === ' ') {
result += tmp; tmp = "";
}
}
return result;
}
console.log(reverse1("I like this program very much"));
console.log(reverse1(" I like this program very much "));
console.log(reverse1("abc"));