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Efficiently filtering out 'None' items in a list comprehension in which a function is called

I have a list comprehension that calls a function which potentially returns None.

>>> f = lambda x: x if x < 3 else None
>>> l = [f(x) for x in [1,2,3,4]]
[1, 2, None, None]

I'd like to have the list comprehension as above, without the 'None' entries.

What's a more efficient way to do the following, without creating additional overhead, and while retaining the efficiency of the list comprehension?

>>> filter(None, [f(x) for x in [1,2,3,4]])
[1, 2]
over 4 years ago · Santiago Trujillo
1 answers
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Add an if into your comprehension like:

l = [y for y in (f(x) for x in [1,2,3,4]) if y is not None]

By placing a Generator Expression inside the list comprehension you will only need to evaluate the function once. In addition the generator expression is a generator so takes no extra intermediate storage.

Python 3.8+

As of Python 3.8 you can use an Assignment Expression (:=) (AKA: Named Expressions or the Walrus Operator) to avoid multiple evaluations of f() like:

l = [y for x in [1,2,3,4] if (y := f(x)) is not None]
over 4 years ago · Santiago Trujillo Report
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