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JS Agregar a la matriz con el operador de propagación si no es NULL - Sintaxis de expresión

Necesito obtener una matriz resultante de la matriz original props.ids y condicionalmente (si no es NULL) la variable selectedId adjunta. Lo siguiente funciona, pero la sintaxis no parece correcta. Necesito el selectedId && para verificar si no es NULL, y si es así, agregue el ID selectedId . ¿Hay una mejor sintaxis para esta pequeña expresión?

 const [selectedId, setSelectedId] = useState(null); obj = { 'exclude':[...props.ids, selectedId && selectedId]} }
about 4 years ago · Juan Pablo Isaza
3 answers
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0

De una sola línea

 const [selectedId, setSelectedId] = useState(null); obj = { exclude:[...props.ids, ...(selectedId === null ? [] : [selectedId])]} }

Forma apropiada

 const [selectedId, setSelectedId] = useState(null); obj = { exclude: [...props.ids] } if (selectedId !== null) { obj.exclude.push(selectedId) }
about 4 years ago · Juan Pablo Isaza Report

0

Además de la respuesta de Ananth, también podría usar el operador ternario en línea

 const ids = [1, 2, 3]; let item = null; let resultWhenNull = [...ids, ...(item ? [item] : [])]; console.log(resultWhenNull); item = 4; const resultWhenNonNull = [...ids, ...(item ? [item] : [])]; console.log(resultWhenNonNull);

about 4 years ago · Juan Pablo Isaza Report

0

puede usar el operador ternario o una declaración if simple para lograr esto

 const [selectedId, setSelectedId] = useState(null); const obj = {}; // if selectedId is present append selectedId, else return array of props.ids obj['exclude'] = selectedId ? [...props.ids, selectedId] : [...props.ids] 

 const value = false; const props = [1, 2, 3]; const valToAppend = 4; const obj = {}; obj['test'] = value ? [...props, valToAppend] : [...props]; console.log(obj);

about 4 years ago · Juan Pablo Isaza Report
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