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La mejor manera de dividir una cadena y crear la siguiente matriz: '1-2-3' -> ['1', '1-2', '1-2-3']

la cadena es algo como esto:

 const string = '1-2-3-4-5-6-7-...-n';

y necesito una matriz como esta:

 const arr = ['1', '1-2', '1-2-3', '1-2-3-4', '1-2-...-n'];

He entrado en esto hasta ahora:

 const str = '1-2-3'; const arr = []; let actualValue = ''; const splitArray = str.split('-'); for (let i = 0; i < splitArray.length; i++) { if (actualValue) actualValue = actualValue + '-' + splitArray[i]; else actualValue = splitArray[i]; arr.push(actualValue); }
about 4 years ago · Juan Pablo Isaza
2 answers
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0

¿Quizás esta solución te convenga?

 const result = "1-2-3-4-5-6-7-8-9".split("-").reduce((prev, curr) => { const last = prev.slice(-1); last.push(curr); prev.push(last.join("-")); return prev; }, []); console.log(result);

about 4 years ago · Juan Pablo Isaza Report

0

yo prefiero

 const str = '1-2-3'; const arr = []; let actualValue = ''; const splitArray = str.split('-'); if (splitArray.length) { actualValue = splitArray[0]; arr.push(actualValue); } for (let i = 1; i < splitArray.length; i++) { actualValue = actualValue + '-' + splitArray[i]; arr.push(actualValue); } console.log(arr);

para reducir el número de comparaciones.

about 4 years ago · Juan Pablo Isaza Report
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