This is my JSON file output:
let employees = [{
"id":1,
"name":"Lann",
"username":"brot",
"email":"b@sd.com",
"address": {
"city":"Gweh",
"zipcode":"92998-3874",
"geo": {
"lat":"45",
"lng":"77"
}
}
}]
How I get id, name and email from that like below:
{
"id":1,
"name":"Lann",
"email":"b@sd.com"
}
You can archive using map.
let employees = [{
"id":1,
"name":"Lann",
"username":"brot",
"email":"b@sd.com",
"address":{
"city":"Gweh",
"zipcode":"92998-3874",
"geo":{
"lat":"45",
"lng":"77"
}
}
}]
const data = employees.map(o => ({ id: o.id, name: o.name, email:o.email }));
console.log(data[0]);If your array has only one element you can just access the info, no need to build another array like this: employees[0].id , employees[0].name, employees[0].email or you can just extract an object using Object Destructuring
let employees = [{
"id": 1,
"name": "Lann",
"username": "brot",
"email": "b@sd.com",
"address": {
"city": "Gweh",
"zipcode": "92998-3874",
"geo": {
"lat": "45",
"lng": "77"
}
}
}];
const picked = (({ id, name, email }) => ({ id, name, email }))(employees[0]);
console.log(picked);but if your array has more employees, i think what you need to do is search by id or name and get back just an object with minimal info, you can do that like this
let employees = [{
"id": 1,
"name": "Lann",
"username": "brot",
"email": "b@sd.com",
"address": {
"city": "Gweh",
"zipcode": "92998-3874",
"geo": {
"lat": "45",
"lng": "77"
}
}
}];
let employee = employees.find(o => o.name === 'Lann');
let picked = (({ id, name,email }) => ({ id, name,email }))(employee);
console.log(picked);let employees = [{
"id":1,
"name":"Lann",
"username":"brot",
"email":"b@sd.com",
"address":{
"city":"Gweh",
"zipcode":"92998-3874",
"geo":{
"lat":"45",
"lng":"77"
}
}}];
// Destructuring array
const [employee] = employees;
employee is an object and you can access its property normally as you do with other objects. For getting id, name, username:**employee.id;
employee.name;
employee.username;