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Campo de pedido personalizado con Django Rest Framework

tengo un modelo como

 class MyModel(models.Model): COLOR_CODES = ['RED', 'YELLOW', 'GREEN'] name = models.CharField(db_column='name', max_length=200, blank=False, null=False, unique=True) colorCode = EnumField(db_column='color_code', choices=COLOR_CODES, null=False, default='GREEN') class Meta: managed = True db_table = 'MyModel' ordering = ['colorCode']

Me gustaría ordenar el juego de preguntas por colorCode, pero no como elementos VERDES, ROJOS, AMARILLOS. Quiero hacer el pedido como artículos ROJOS, AMARILLOS, VERDES.

¿Es posible? ¿Hay algo como Java Comparator? Gracias por adelantado.

over 4 years ago · Santiago Trujillo
1 answers
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Podría usar la función sorted de Python, pero para aprovechar las consultas de Django:

 from django.db.models import Value, IntegerField, When, Case # Don' t set the default order in the model (this also improves performance), simply write this query when you need this particular order MyModel.objects.annotate(order=Case(When(colorCode='RED', then=0), When(colorCode='YELLOW', then=1), default=Value(2), output_field=IntegerField())).order_by('order')

De lo contrario, podría cambiar su modelo:

 from enum import Enum class MyModel(models.Model): class ColorCodes(Enum): # In the admin interface you will see 'red' and not '0r' (so don't worry about ugly names), the second value is stored in the database and is used for order the queryset red = ('red', '0r') yellow = ('yellow', '1y') green = ('green', '2g') @classmethod def get_value(cls, member): return cls[member].value[0] colorCode = CharField(db_column='color_code', null=False, default=ColorCodes.get_value('green'), max_length=2, choices=[x.value for x in ColorCodes]) class Meta: managed = True db_table = 'MyModel' ordering = ['colorCode']
over 4 years ago · Santiago Trujillo Report
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