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Array.Filter() usando una función de devolución de llamada para comparar dos matrices

En lugar de usar una función anónima, ¿cómo convertiría el siguiente elemento => arr2.includes (elemento) en una función con nombre que luego podría pasar?

 const ArrayOverlap = (arr1, arr2) =>{ let newArr = []; return newArr = arr1.filter(element => arr2.includes(element)); }

Si tuviera que hacer algo como

 const ArrayOverlap = (arr1, arr2) =>{ let newArr = []; return newArr = arr1.filter(bothIncluded(arr1, arr2)); } function bothIncluded(arr1, arr2){ for(const item of arr1){ return arr2.includes(item); }
about 4 years ago · Juan Pablo Isaza
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Pude hacer que funcionara usando la opción thisArg al llamar a la función de devolución de llamada.

 const ArrayOverlap = (arr1, arr2) =>{ let newArr = []; return newArr = arr1.filter(checkMe, arr2); function checkMe(element){ return this.includes(element); }
about 4 years ago · Juan Pablo Isaza Report
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