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React native .shuffle()
export default function App() {


  Array.prototype.shuffle = function () {
    let rnum=[]
    let random = this
    for (let i= 0; i < random.length; i++){
      let randomizer = Math.floor(Math.random()*(this.length));


      rnum.push(randomizer)
     
    }
    console.log(rnum)
    
    
  }
  let random = [0,1,2,3,4].shuffle()

This is my current code. It currently prints a random array of the "random" numbers, how ever im trying to print all the available numbers without any one number repeating itself inside of the "rnum" array. If anyone could help me out id be gratefull!

about 4 years ago · Juan Pablo Isaza
1 answers
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0

  let index= this.length, randomIndex

  while(index != 0) {
    randomIndex = Math.floor(Math.random()*index)
    index--

    [this[index], this[randomIndex]] = [this[randomIndex], this[index]]
  }
  return this
  
  
}
var random = [0,1,2,3,4].shuffle()
  console.log(random) 

I solved the problem by using Samuel Goldenbaum's suggestion to look at a previous solution in JS "How to randomize (shuffle) a JavaScript array?". I simply had tu replace all replace "array" with "this"!

about 4 years ago · Juan Pablo Isaza Report
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