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Solicitud de Wordpress ajax en javascript puro (¿dónde poner la acción?)

Solicitud de wordpress ajax en jquery.

La solicitud de ajax en jquery funciona, pero estoy tratando de usar JavaScript puro.

¿Cómo puedo convertir este código en javascript puro?

 $('#camitonContactForm').submit(function(event){ event.preventDefault(); isValidationOn = true; validateInputs(); let formaction = $('#camitonContactForm').data('url'); let forminput = $('#camitonContactForm').serialize(); let noncecheck = $('#camitonContactForm').data('nonce'); ; let formdata = new FormData; formdata.append('action', 'contact_message'); formdata.append('nonce', noncecheck); formdata.append('contact_message',forminput); $.ajax(formaction, { type:'POST', data:formdata, processData: false, contentType:false, success: function(res){ }, error: function(err){ alert(err.responseJSON.data); } });

Aquí traté de escribirlo en javascript puro pero no funciona.

 form.addEventListener('submit', (e) => { e.preventDefault(); isValidationOn = true; validateInputs(); //form action let formwrapper = document.getElementById('camitonContactForm'); let formaction = formwrapper.getAttribute('data-url'); //form nonce let noncecheck = formwrapper.getAttribute('data-nonce'); //form let forminput = serialize(formwrapper); var formdata = new FormData(form); /* formdata.append('action', 'contact_message'); formdata.append('nonce', noncecheck); formdata.append('contact_message',forminput); */ let ajax = new XMLHttpRequest(); ajax.open("POST", formaction, true); ajax.onreadystatechange = function() { if(ajax.responseText == 4 && ajax.status == 200){ if(ajax.responseText == "success"){ }else{ statusSection.innerHTML = ajax.responseText; btnsection.disabled = false; alert('well something wrong'); } } } ajax.send(formdata); });

la función de serialización que encontré en este enlace a continuación forma serializar javascript (sin marco)

about 4 years ago · Juan Pablo Isaza
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