I'm struggling to figure out a Regex pattern for JavaScript that will trim a path of it's preceding and trailing slashes (or hashes/extensions)
For example:
path/
/path
/folder/path/
/folder/folder/path
/folder/path#hash
/folder/path.ext
Should return:
path
path
folder/path
folder/folder/path
folder/path
folder/path
I felt like I was getting close with the following, but it only selects text without any slashes, hashes, or periods.
^([^\\\/\#\.]*)(?![\#\.\\\/].*$)/gm
I'm trying to use this for Regex in a vuetify text-field validation, if that's at all helpful.
I ended up with this regex slug
/^(?![\#\/\.\$\^\=\*\;\:\&\?\(\)\[\]\{\}\"\'\>\<\,\@\!\%\`\~\s])(?!.*[\#\/\.\$\^\=\*\;\:\&\?\(\)\[\]\{\}\"\'\>\<\,\@\!\%\`\~\s]$)[^\#\.\$\^\=\*\;\:\&\?\(\)\[\]\{\}\"\'\>\<\,\@\!\%\`\~\s]*$/
This is how it is achieved with no lookbehinds (they are still rejected in Safari :():
^(?![#\/.])(?!.*[#\/.]$).*
See regex proof. And...
EXPLANATION
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^ the beginning of the string
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(?! look ahead to see if there is not:
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[#\/.] any character of: '#', '\/', '.'
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) end of look-ahead
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(?! look ahead to see if there is not:
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.* any character except \n (0 or more times
(matching the most amount possible))
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[#\/.] any character of: '#', '\/', '.'
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$ before an optional \n, and the end of
the string
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) end of look-ahead
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.* any character except \n (0 or more times
(matching the most amount possible))