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How do you sanitize a string to pass a regex?

I have a regex validation I need my string to pass.

/^[0-9a-zA-Z-]+$/

I want to create a function that sanitizes the string for it to pass the regex. I thought of doing something like

string.replace(/^[0-9a-zA-Z-]+$/,"");

Except I need to invert the above regex.

I tried to look up how to invert a regex but nothing seems to show up.

about 4 years ago · Juan Pablo Isaza
2 answers
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0

Try this string.replace(/\W/g,""). Also check this web site i always use it to test regular expressions, it also has hints on the right bottom

about 4 years ago · Juan Pablo Isaza Report

0

Negate the collection using ^ inside the []

const str = `abc*ç%ABC&(/())12345=?`

const newString = str.replace(/[^0-9a-zA-Z-]/g,"");

console.log(newString)

about 4 years ago · Juan Pablo Isaza Report
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